18.3 Review problems
Problem 18.3.1. A regression with \(k = 4\) coefficients is fitted to \(n = 60\) observations, with \(\text {RSS}_U = 120\). Imposing two linear restrictions raises the residual sum of squares to \(\text {RSS}_R = 150\).
- (a)
- Carry out the \(F\) test at the \(5\%\) level.
- (b)
- Compute the Wald, likelihood ratio and Lagrange multiplier statistics, and verify the inequality between them.
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Solution. (a) \(F = \bigl ((150 - 120)/2\bigr )/\bigl (120/56\bigr ) = 15/2.143 = 7.0\), against the \(5\%\) point \(F_{2,56} = 3.16\): the restrictions are rejected.
(b) By Theorem 9.3.1, \(W = 60(30)/120 = 15.0\), \(\text {LR} = 60\log (150/120) = 13.39\) and \(\text {LM} = 60(30)/150 = 12.0\), so \(W \geq \text {LR} \geq \text {LM}\). All exceed the \(\chi ^2_2\) point \(5.99\). Also \(W = \frac {n}{n-k}qF = \frac {60}{56}(2)(7.0) = 15.0\).
Problem 18.3.2. A student regresses the log of a country’s real GDP on the log of its money supply, using \(40\) annual observations, and reports \(R^2 = 0.97\), a slope of \(1.8\) with \(t = 34\), and a Durbin–Watson statistic of \(0.42\). ADF tests do not reject a unit root in either series, and the ADF statistic of the regression residuals is \(-1.8\).
- (a)
- What do you conclude about the regression?
- (b)
- What should the student do instead?
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Solution. (a) \(R^2 > d\), the classic sign of a spurious regression (Theorem 12.2.5). The residual ADF statistic \(-1.8\) is far above the Engle–Granger \(5\%\) critical value \(-3.34\), so the null of no cointegration is not rejected: the residuals are \(I(1)\), the \(t\) ratio of \(34\) is meaningless, and the regression says nothing about the relation between money and output.
(b) Since the series are \(I(1)\) but not cointegrated, model the relation in differences (growth rates), for instance in a VAR in differences, with tests of Granger causality; or look for omitted variables (prices, interest rates) with which the two might be cointegrated, and test with Johansen’s method.
Problem 18.3.3. In a cross-section of \(500\) firms, investment is regressed on cash flow and Tobin’s \(q\). The White test gives \(nR^2 = 41.2\) on \(5\) degrees of freedom. The conventional standard error of the cash flow coefficient is \(0.012\) and its robust (HC3) standard error is \(0.021\); the estimate is \(0.045\).
- (a)
- Is there heteroscedasticity? Does it bias the estimate?
- (b)
- Is cash flow significant?
- (c)
- A critic argues that \(q\) is measured with error. What does this imply, and how could it be addressed?
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Solution. (a) \(41.2\) far exceeds the \(\chi ^2_5\) point \(11.07\), so homoscedasticity is rejected. Heteroscedasticity does not bias least squares (Theorem 9.4.1); it invalidates the conventional standard errors.
(b) With the robust standard error, \(t = 0.045/0.021 = 2.14\), significant at \(5\%\) but much less so than the conventional \(t = 3.75\) suggests.
(c) Measurement error in \(q\) attenuates its coefficient (Theorem 13.1.1) and, because cash flow is correlated with true \(q\), biases the cash flow coefficient too, typically upwards, since cash flow picks up the part of investment opportunities that mismeasured \(q\) misses. The remedy is IV: instrument \(q\) with lagged values or an alternative measure, and test with Hausman’s statistic.
Problem 18.3.4. For the market model of Example 14.1.2, suppose weather also shifts demand (people buy less in bad weather), so that both equations contain \(w\) and only the demand equation contains income.
- (a)
- Which equation is identified?
- (b)
- What is the 2SLS estimator of the identified equation, and what are its instruments?
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Solution. (a) Demand now excludes no exogenous variable, so it fails the order condition and is underidentified. Supply excludes income, which appears in demand, so it is exactly identified (Theorem 14.2.1).
(b) Regress \(q\) on \(p\) and \(w\) in the supply equation, with instruments the constant, \(w\) and income. Exactly identified, it equals the IV estimator and ILS: income shifts demand along the supply curve.
Problem 18.3.5. In a panel of \(1000\) workers over \(4\) years, the effect of union membership on log wages is estimated as \(0.081\) (s.e. \(0.012\)) by fixed effects and \(0.064\) (s.e. \(0.007\)) by random effects.
- (a)
- Carry out the Hausman test.
- (b)
- Interpret the direction of the difference.
- (c)
- Most workers never change union status. What does this imply for the fixed effects estimate?
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Solution. (a) \(H = (0.081 - 0.064)^2/(0.012^2 - 0.007^2) = 0.000289/0.000095 = 3.04\), below the \(\chi ^2_1\) point \(3.84\): random effects is not rejected at \(5\%\), though the evidence is borderline (at \(10\%\), \(2.71\), it would be).
(b) Random effects is lower, which suggests that union members have, if anything, lower unobserved earning power; unions may organise workers who would otherwise earn less, so the between comparison understates the union effect.
(c) The fixed effects estimate is identified only by switchers, whose changes may be few and partly due to misclassification, which attenuates it strongly in first differences or within data (Section 16.2). Its large standard error reflects the small within variation.
Problem 18.3.6. A probit model of labour force participation has, for a typical woman, index \(x'\hat \beta = 0.4\), and the coefficient of years of education is \(0.6\) per decade.
- (a)
- Find her predicted probability of participation and the marginal effect of education.
- (b)
- A Heckman wage equation is to be estimated for the participants. Suggest an exclusion restriction, and explain why one is needed.
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Solution. (a) \(\Phi (0.4) = 0.655\), and the marginal effect is \(\phi (0.4)(0.6) = 0.368 \times 0.6 = 0.221\) per decade: another ten years of education would raise the probability by \(22\) points, or about \(2.2\) points per year at this point on the curve.
(b) The number of young children, or non-labour income such as a spouse’s earnings, affects the decision to work but plausibly not the wage offered. Without such a variable the selection term \(\lambda (z'\gamma )\) is nearly collinear with the wage regressors, and the correction is identified only by the functional form (Section 17.3).
Problem 18.3.7. An error correction model for consumption is estimated as \[ \Delta c_t = 0.4\Delta y_t - 0.25(c_{t-1} - 0.9y_{t-1}) + \hat \varepsilon _t , \] with \(c\) and \(y\) the logs of consumption and income.
- (a)
- What are the impact and long-run elasticities of consumption with respect to income?
- (b)
- What is the half-life of a disequilibrium?
- (c)
- Write the equivalent ADL model, and check whether it satisfies the common factor restriction.
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Solution. (a) The impact elasticity is \(0.4\) and the long-run elasticity \(0.9\).
(b) A quarter of the gap closes each period, so \(\phi = 0.75\), and the half-life is \(\log 0.5/\log 0.75 = 2.4\) periods.
(c) From Theorem 12.5.1, \(1 - \phi = 0.25\), \(\beta _0 = 0.4\) and \(\theta = (\beta _0 + \beta _1)/(1 - \phi ) = 0.9\), so \(\beta _1 = 0.225 - 0.4 = -0.175\): \(c_t = 0.75c_{t-1} + 0.4y_t - 0.175y_{t-1} + \varepsilon _t\). The common factor restriction requires \(\beta _1 = -\phi \beta _0 = -0.3\); it fails, consistently with the impact and long-run elasticities being different.
Problem 18.3.8. Classify each of the following as a problem of bias or of standard errors only, and name the method you would use.
- (a)
- Monthly sales regressed on advertising, with residual autocorrelation \(0.6\) and strictly exogenous advertising.
- (b)
- Hours of work regressed on the wage for a sample of workers only.
- (c)
- Crop yield regressed on fertiliser use across farms, where better farmers use more fertiliser.
- (d)
- Test scores regressed on a school-level policy, with pupils as observations.
- (e)
- Expenditure on cigarettes, zero for most households.
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Solution. (a) Standard errors only, since advertising is exogenous: HAC standard errors or FGLS (Section 11); also consider a dynamic model. (b) Bias from sample selection: Heckman’s model with an exclusion restriction (Section 17.3); the wage is also endogenous, which calls for IV. (c) Bias from an omitted variable correlated with the regressor: farm fixed effects with panel data, or an instrument for fertiliser such as its price (Sections 16 and 13). (d) Standard errors only: cluster by school, and note the Moulton factor (Section 16.5). (e) A censored outcome: Tobit or a two-part model (Section 17.2).
Problem 18.3.9. In the model \(y = \beta x^* + \varepsilon \), both \(y\) and \(x\) are measured with error: \(x = x^* + m\) and \(y_{\text {obs}} = y + n\), with \(m\) and \(n\) independent of each other and of \(x^*\) and \(\varepsilon \). With \(\beta = 0.8\), \(\Var (x^*) = 36\) and \(\Var (m) = 9\), find the probability limit of the least squares slope. Does the error in \(y\) matter?
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Solution. The reliability of \(x\) is \(36/45 = 0.8\), so \(\plim b = 0.8 \times 0.8 = 0.64\) by Theorem 13.1.1. The error \(n\) in \(y\) only adds to the disturbance: it is uncorrelated with \(x\), so it does not affect the probability limit, but it increases the variance of \(b\).
Problem 18.3.10. A study estimates the Euler equation of Section 15.5 by two-step GMM with \(6\) instruments and \(2\) parameters, obtaining \(J = 9.1\). A second specification adds \(4\) more lags as instruments, and obtains \(J = 11.0\) with the same estimates of the parameters.
- (a)
- Test the overidentifying restrictions in each case.
- (b)
- Why might the second test be less reliable than the first?
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Solution. (a) The first has \(6 - 2 = 4\) degrees of freedom, with \(5\%\) point \(9.49\): \(J = 9.1\) does not quite reject. The second has \(8\), with \(5\%\) point \(15.51\): \(11.0\) does not reject.
(b) With \(10\) instruments the weighting matrix \(\hat S\) is a \(10 \times 10\) matrix estimated from the data, and with many moments its inverse is poorly estimated, which weakens the \(J\) test and biases two-step GMM (Section 15.5). A \(J\) statistic that grows less than its degrees of freedom when instruments are added is a common sign of this loss of power, not evidence that the model fits better.
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