3.7 Expected Number of Visits
Let \(V^{(n)}_{ij}\) denote the total number of visits that the chain makes to State \(j\) in the first \(n\) steps from step 0
to step \(n- 1\) starting from State \(i\).
Given \(X_0 = i\), we define an indicator variable at step \(k\geq \) as \[I_{ij}^{(k)} = \begin {cases} 1 & \text {if}\hspace {0.3cm} X_k = j\hspace {0.5cm}\text {i.e}\hspace {0.5cm} P^{(k)}_{ij} > 0\\ 0 & \text {otherwise}\\ \end {cases}\] Hence \(E\left (I_{ij}^{(k)}\right ) = P_{ij}^{(k)}\).
Clearly \[V_{ij}^{(n)} = \sum ^{n - 1}_{k = 0} I_{ij}^{(k)}\]
\[E\left (V_{ij}^{(n)}\right ) = \sum ^{n-1}_{k = 0} E\left (I_{ij}^{(k)}\right ) = \sum ^{n -1}_{k = 0} P^{(k)}_{ij}\hspace {0.3cm} \cdots \cdots \hspace {0.5cm} (*)\] Let \[V^{(n)} = \begin {pmatrix} E\left (V_{ij}^{(n)}\right )\\ \end {pmatrix}_{(i,j)\in S}\]
Hence in matrix form equation \((*)\) can be written as \[V^n = I + P + P^2 + \, \cdots \, + P^{n -1}\]
Example 3.7.1. A cab driver drives business in three adjoining cities \(A, B\) and \(C\).
Let the one-hour transition matrix be
\[P = \bordermatrix {~ & A & B & C \cr A & .4 & .1 & .5 \cr B & .2 & .2 & .6 \cr C & .3 & .4 & .3 \cr }\]
\[V^{(4)} = I + P + P^2 + P^3 = \begin {pmatrix} 2.04 & .61 & 1.35\\ .8 & 1.75 & 1.45\\ .9 & .9 & 2.21\\ \end {pmatrix}.\] If the driver States from city \(A\) at 8 a.m, then total visits upto time 11 a.m to city \(A\) will be 2.04 to city \(B\) will be .61 to and to city C will be 1.35.
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