3.9 Three-Way Analysis Of Variance
In a three-way model there are three factors of interest \[Y_{ijlm}=\mu _{ijl}+\varepsilon _{ijlm}\] \[i=1,2,\ldots ,a\qquad j=1,2,\ldots ,b\qquad l=1,2,\ldots ,k\qquad m=1,2,\ldots , n\] \[ \varepsilon _{ijlm}\thicksim ^{iid}(0,\sigma ^2)\]
There are \(abk\) treatments.
Factor \(A\), has \(a-\) levels
Factor \(B\), has \(b-\) levels
Factor \(C\), has \(k-\) levels
\[Y_{ijlm}=\mu + \alpha _i + \beta _j + \tau _l + (\alpha \beta )_{ij} + (\alpha \tau )_{il} + (\beta \tau )_{jl}+(\alpha \beta \tau )_{ijl}+\varepsilon _{ijlm}\] \[\sum \alpha _i=\sum \beta _j=\sum (\alpha \beta )_{ij}=\sum (\alpha \tau )_{il}=\sum (\beta \tau )_{jl}=\sum (\alpha \beta \tau )_{ijl}=0\]
- \(\mu =\)
- \(\alpha _i=\)
- \(\beta _j=\)
- \(\tau _l=\)
- \((\alpha \beta )_{ij}=\)
- \((\alpha \tau )_{il}=\)
- \((\beta \tau )_{jl}=\)
- \((\alpha \beta \tau )_{ijl}=\) interaction of factor \(A\) at the \(i^{\text {th}}\) level with factor \(B\) at the \(j^{\text {th}}\) level and with factor \(C\) at the \(l^{\text {th}}\) level.
\begin {align*} Y_{ijlm}-\overline {Y}.... = & \underbrace {\overline {Y}_i...-\overline {Y}....}_{\hat {\alpha }_i} + \underbrace {\overline {Y}._j..-\overline {Y}....}_{\hat {\beta }_j} + \underbrace {\overline {Y}..l.-\overline {Y}....}_{\hat {\tau }} + \underbrace {\overline {Y}_{ij}..-\overline {Y}_i...-\overline {Y}._j..+\overline {Y}....}_{(\hat {\alpha }\hat {b})_{ij}}\\ & + \underbrace {\overline {Y}_i._l.-\overline {Y}_i...-\overline {Y}.._l.+\overline {Y}....}_{(\alpha \hat {\tau })_{il}}+\underbrace {\overline {Y}._{jl}.-\overline {Y}._j..-\overline {Y}.._l.-\overline {Y}....}_{(\beta \tau )_{jl}}\\ & + \underbrace {\overline {Y}_{ijl}.-\overline {Y}_i...-\overline {Y}._j..-\overline {Y}.._l.-\overline {Y}....}_{(\alpha \beta \tau )_{ijl}} + \underbrace {Y_{ijlm}-\overline {Y}_{ijl}.}_{\hat {\varepsilon }_{ijlm}} \end {align*}
Squaring both sides of the identity above and adding, all the cross-product terms vanish, leaving \begin {align*} SST = & SSA + SSB + SSC + SSAB + SSAC + SSBC + SS(ABC) + SSE\\ abkn-1 = & (a-1) + (b-1) + (k-1) + (a-1)(b-1) + (a-1)(k-1) + (b-1)(k-1)\\ & + (a-1)(b-1)(k-1)+ abk(n-1)\\ \end {align*}
\(SST = \displaystyle {\sum _i\sum _j\sum _l\sum _m\big (Y_{ijlm}-\overline {Y}....\big )^2}\)
\(SSA = \displaystyle {bkn\sum ^a_{i=1}\big (\overline {Y}_i...-\overline {Y}....\big )^2}\)
\(SSB = \displaystyle {akn\sum ^b_{j=1}\big (\overline {Y}._j..-\overline {Y}....\big )^2}\)
\(SSC = \displaystyle {abn\sum ^k_{l=1}\big (\overline {Y}.._l.-\overline {Y}....\big )^2}\)
\(SS(AB) = \displaystyle {kn\sum ^a_{i=1}\sum ^b_{j=1}\big (\overline {Y}_{ij}..-\overline {Y}_i...-\overline {Y}._j..+\overline {Y}....\big )^2}\)
\(SS(AC) = \displaystyle {bn\sum ^a_{i=1}\sum ^k_{l=1}\big (\overline {Y}_i._l.-\overline {Y}_i...-\overline {Y}.._l.+\overline {Y}....\big )^2}\)
\(SS(BC) =\displaystyle {an\sum ^b_{j=1}\sum ^k_{l=1}\big (\overline {Y}._{jl}.-\overline {Y}._j..-\overline {Y}.._l.-\overline {Y}....\big )^2}\)
\(SS(ABC) = \displaystyle {n\sum _i\sum _j\sum _l\big (\overline {Y}_{ijl}.-\overline {Y}_i...-\overline {Y}._j..-\overline {Y}.._l.+\overline {Y}....\big )}\)
\(SSE = \displaystyle {\sum _i\sum _j\sum _l\sum _m\big (Y_{ijlm}-\overline {Y}_{ijl}.\big )^2}\)
Example 3.9.1. Yields of Soya Bean from three \((A)\)seed types \((I,II,III)\), under two levels \((C)\) of water
(Low, High) and two levels \((B)\) of fertilizers (Low, High).
| Low Water | High Water
| |||
| Seed type | Low (fert) | High (fert) | Lower (fert) | High (fert) |
|
\(I\) | 18.6 | 10.2 | 12.3 | 12.3 |
| 18.8 | 10.5 | 10.9 | 10.7 | |
| 15.8 | 8.5 | 10.7 | 12.0 | |
| 17.9 | 10.6 | 11.8 | 11.8 | |
|
\(II\) | 19.4 | 14.7 | 13.2 | 10.3 |
| 18.9 | 17.8 | 15.5 | 8.5 | |
| 18.4 | 15.6 | 11.0 | 7.1 | |
| 18.9 | 16.5 | 11.8 | 6.5 | |
|
\(III\) | 15.9 | 20.9 | 19.4 | 13.2 |
| 16.5 | 21.0 | 21.2 | 13.5 | |
| 17.2 | 21.3 | 20.4 | 12.8 | |
| 16.5 | 20.4 | 20.3 | 15.2 | |
\begin {align*} Y_{ijlm} & = \mu _{ijl} + \varepsilon _{ijlm}\\ i & = 1,2,3\implies a=3\\ j & = 1,2 \implies b=2\\ l & = 1,2 \implies k=2\\ m & = 1,2,3,4 \implies n=4\\ abkn & = 48 \end {align*}
| Source of | SS | df | MS | F |
| Variation | ||||
| \(A\) | \(SS(A)=229.26\) | 2 | 114.63 | |
| Seed type | ||||
| \(B\) | \(SS(B)=100.63\) | 1 | 100.63 | |
| Fertilizer | ||||
| \(C\) | \(SS(C)=163.12\) | 1 | 163.17 | |
| Water | ||||
| \(A\times B\) | \(SS(AB)=18.27\) | 2 | 9.135 | |
| \(A\times C\) | \(SS(AC)=68.53\) | 2 | 34.165 | |
| \(B\times C\) | \(SS(BC) = 8.25\) | 1 | 8.25 | |
| \(A\times B \times C\) | \(SS(ABC) = 183.39\) | 2 | 91.69 | |
| Error | \(SSE=43.49\) | 36 | 1.208 | |
| Total | \(SST=814.99\) | 47 | ||
The three-way layout and ANOVA is just an extension of a two-factor lay out and ANOVA.
However, it is tedious therefore the three-way design we will discuss in detail is an incomplete
three-way lay out in which the three factors are all at the same levels. This design is called the Latin
square design.
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